(x-2)(1x^2-8x+7)=0

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Solution for (x-2)(1x^2-8x+7)=0 equation: 


Simplifying
(x + -2)(1x2 + -8x + 7) = 0

Reorder the terms:
(-2 + x)(1x2 + -8x + 7) = 0

Reorder the terms:
(-2 + x)(7 + -8x + 1x2) = 0

Multiply (-2 + x) * (7 + -8x + 1x2)
(-2(7 + -8x + 1x2) + x(7 + -8x + 1x2)) = 0
((7 * -2 + -8x * -2 + 1x2 * -2) + x(7 + -8x + 1x2)) = 0
((-14 + 16x + -2x2) + x(7 + -8x + 1x2)) = 0
(-14 + 16x + -2x2 + (7 * x + -8x * x + 1x2 * x)) = 0
(-14 + 16x + -2x2 + (7x + -8x2 + 1x3)) = 0

Reorder the terms:
(-14 + 16x + 7x + -2x2 + -8x2 + 1x3) = 0

Combine like terms: 16x + 7x = 23x
(-14 + 23x + -2x2 + -8x2 + 1x3) = 0

Combine like terms: -2x2 + -8x2 = -10x2
(-14 + 23x + -10x2 + 1x3) = 0

Solving
-14 + 23x + -10x2 + 1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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